addend造句
例句與造句
- Thus, the augend and addend must each be small enough to fit within one memory location .
由此可見(jiàn)，加數(shù)和被加數(shù)都應(yīng)足夠小，以便能夠適合地裝入一個(gè)存儲(chǔ)單元。 - Thus, the augend and the addend must each be small enough to fit within one memory location .
由此可見(jiàn)，加數(shù)和被加數(shù)都應(yīng)足夠小，以便能夠合適地裝入一個(gè)存儲(chǔ)單元。 - Switch the two addends and the sum remains the same
生：交換兩個(gè)加數(shù)的位置，和不變。 - Stability of multiplier - addend model and the macro - control policies
加速數(shù)模型的穩(wěn)定性與宏觀調(diào)控政策 - Switch the two addends and the sum remains the same
7生：兩個(gè)數(shù)相加，交換加數(shù)的位置，他們的和不變。 - It's difficult to find addend in a sentence. 用addend造句挺難的
- In addition , switch the two addends and the sum remains the same
生：兩個(gè)數(shù)相加，交換加數(shù)的位置，他們的和不變。 - 137 and 357 are the addends . the answer 494 is the sum
生： 137和357在加法算式中叫做加數(shù)。他們相加的得數(shù)494叫做和。 - The two numbers being added are the addends . the answer is the sum
3電腦出示結(jié)論：相加的兩個(gè)數(shù)叫做加數(shù)，加的數(shù)叫做和。 - Multiplication is the easier way to find the sum of same addends
根據(jù)學(xué)生的回答總結(jié)得出：求幾個(gè)相同加數(shù)的和的簡(jiǎn)便運(yùn)算，叫做乘法。 - In addition , add the addends in any order and the sum remains the same
師：這就是加法結(jié)合律。利用加法結(jié)合律，可以進(jìn)行簡(jiǎn)便運(yùn)算。請(qǐng)做下列題。 - Subtract one addend from the sum . if you can get the other addend , you ' re right
加法的驗(yàn)算。從算出的和里減去一個(gè)加數(shù)，看是不是等于另一個(gè)加數(shù)。 - One addend adds one number . the other addend subtracts the same number . the sums are the same
小結(jié)：一個(gè)加數(shù)增加幾，另一個(gè)加數(shù)減少幾，增加和減少的數(shù)相等，它們的和仍是10 。 - This demonstrates the operation addition performed on two whole numbers , two and three ( known as addends , ) which result in a sum ( total ) of five circles
以上演示了兩個(gè)整數(shù)的加法運(yùn)算，兩個(gè)整數(shù)分別為2和3 （是作為加數(shù)） ，這樣就得到和是5個(gè)球。 - The way to find an unknown addend from one addend and the sum is called subtraction . this is the essence of subtraction . please read after me
歸納減法的意義：已知兩個(gè)加數(shù)的和與其中的一個(gè)加數(shù)，求另一個(gè)加數(shù)的運(yùn)算，叫做減法。 （讓學(xué)生讀讀。 ） - First , with the coding idea of thomas h . labean " logical computation using dna molecules " , we developed a dna - based addition model of two n - system addend
首先，運(yùn)用labean解決累加異或問(wèn)題的編碼思想，實(shí)現(xiàn)n進(jìn)制的兩個(gè)加數(shù)的加法進(jìn)位問(wèn)題。
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