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triangularizable造句

"triangularizable"是什么意思   

例句與造句

  1. Any complex square matrix is triangularizable.
  2. *PM : commuting matrices are simultaneously triangularizable, id = 7294-- WP guess : commuting matrices are simultaneously triangularizable-- Status:
  3. *PM : commuting matrices are simultaneously triangularizable, id = 7294-- WP guess : commuting matrices are simultaneously triangularizable-- Status:
  4. In other words, ? is triangularizable if there exists a basis such that every element of ? has an upper-triangular matrix representation in that basis.
  5. *PM : proof that commuting matrices are simultaneously triangularizable, id = 7301-- WP guess : proof that commuting matrices are simultaneously triangularizable-- Status:
  6. It's difficult to find triangularizable in a sentence. 用triangularizable造句挺難的
  7. *PM : proof that commuting matrices are simultaneously triangularizable, id = 7301-- WP guess : proof that commuting matrices are simultaneously triangularizable-- Status:
  8. However, while a smooth manifold is not a PL manifold, it carries a canonical PL structure  it is uniquely triangularizable; conversely, not every PL manifold is smoothable.
  9. The basic result is that ( over an algebraically closed field ), the commuting matrices A, B or more generally A _ 1, \ ldots, A _ k are simultaneously triangularizable.
  10. This follows by combining the theorems that, over an algebraically closed field, commuting matrices are simultaneously triangularizable and a normal matrix is diagonalizable  the added result is that these can both be done simultaneously.
  11. This is generalized by Lie's theorem, which shows that any representation of a solvable Lie algebra is simultaneously upper triangularizable, the case of commuting matrices being the abelian Lie algebra case, abelian being a fortiori solvable.
  12. In fact, by Engel's theorem, any finite-dimensional nilpotent Lie algebra is conjugate to a subalgebra of the strictly upper triangular matrices, that is to say, a finite-dimensional nilpotent Lie algebra is simultaneously strictly upper triangularizable.
  13. This can be proven by using induction on the fact that " A " has an eigenvector, by taking the quotient space by the eigenvector and inducting to show that " A " stabilises a flag, and is thus triangularizable with respect to a basis for that flag.
  14. One direction is clear : if the matrices are simultaneously triangularisable, then [ A _ i, A _ j ] is " strictly " upper triangularizable ( hence nilpotent ), which is preserved by multiplication by any A _ k or combination thereof  it will still have 0s on the diagonal in the triangularizing basis.
  15. Over an algebraically closed field such as the complex numbers, all semisimple Lie algebras are splittable ( indeed, not only does the Cartan subalgebra act by triangularizable matrices, but even stronger, it acts by diagonalizable ones ) and all splittings are conjugate; thus split Lie algebras are of most interest for non-algebraically closed fields.

相鄰詞匯

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